A moving coil galvanometer A has 200 turns and a resistance of 100Ω. Another meter B has 100 turns resistance 40Ω. All the other quantities are same in both the cases. The current sensitivity of A is x times of B, the value of x is

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answer is 0002.00.

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Detailed Solution

Current sensitivity (S) = BANC ⇒ S α N ⇒SASB=NANB=200100=21 ⇒SA=2SB

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