First slide

Electrostatic potential

Question

In moving from A to B along an electric field line, the electric field does 6.4 x 10^-19 J of work on an electron. If $ϕ_{1}, ϕ_{2}$ are equipotential surfaces, then the potential difference (V_C - V_A) is

Moderate

A

-4 V
B

4 V
C

Zero
D

64 V

Solution

$Work done by the field, W = q (- dV) = - e (V_{A} - V_{B}) = e (V_{B} - V_{A}) = e (V_{C} - V_{A}) (∵ V_{B} = V_{C}) \Rightarrow (V_{C} - V_{A}) = \frac{W}{e} = \frac{6.4 \times 10^{- 19}}{1.6 \times 10^{- 19}} = 4 V$

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