In moving from A to B along an electric field line, the electric field does 6.4 x 10-19 J of work on an electron. If ϕ1, ϕ2 are equipotential surfaces, then the potential difference (VC - VA) is
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a
-4 V
b
4 V
c
Zero
d
64 V
answer is B.
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Detailed Solution
Work done by the field, W=q(-dV)=-eVA-VB =eVB-VA=eVC-VA ∵VB=VC ⇒ VC-VA=We=6.4×10-191.6×10-19=4 V