In moving from A to B along an electric field line, the work done by the electric field on an electron is 6.4×10−19 J. If ϕ1 and ϕ2 areequipotential surfaces, then the potential difference VC−VA is

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-4 V

4 V

zero

6.4 V

answer is B.

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Detailed Solution

Wel=q(Vi−Vf)or 6.4×10−19=−1.6×10−19(VA−VB)or VA−VB=−4Vor VA−VC=−4V(∵ VB=VC)or VC−VA=4V

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