A moving particle of mass m, makes a head on elastic collision with another particle of mass 2m, which is initially at rest. The percentage loss in energy of the colliding particle on collision, is close to

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

33%

67%

90%

10%

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Conservation of total kinetic energy of the system during collision 12m1u12+12m2u22=12m1v12+12m2v22 or v1=m1−m2m1+m2u1+2m2u2m1+m2 put m1=mm2=2mu2=0 ⇒v1=−u13 Initial kinetic energy of the colliding body is given by, (K.E)i=12mu12 (K.E)f=12m−u132 ΔK.E=(K.E)i−(K.E)f %ΔK.E(K.E)i=89×100=89%≈90%

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th