Questions
A moving particle of mass
detailed solution
Correct option is C
Conservation of total kinetic energy of the system during collision 12m1u12+12m2u22=12m1v12+12m2v22 or v1=m1−m2m1+m2u1+2m2u2m1+m2 put m1=mm2=2mu2=0 ⇒v1=−u13 Initial kinetic energy of the colliding body is given by, (K.E)i=12mu12 (K.E)f=12m−u132 ΔK.E=(K.E)i−(K.E)f %ΔK.E(K.E)i=89×100=89%≈90%Talk to our academic expert!
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