For a moving particle, which of the following options may be correct?

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By Expert Faculty of Sri Chaitanya

vav

vav>vav

vav=0 but vav≠0

vav≠0 but vav=0

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detailed solution

Correct option is B

vav=stand d≤|s|. Also d may be positive ,negative or zero.Now vav=dt∴vav≤vav

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For a moving particle, which of the following options may be correct?

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