Moving with uniform acceleration, a body covers 150m during  10s so that it covers 24m during  10th sec. Find the initial velocity

Let initial velocity of the body be u and ‘a’ be its accelerationGiven that  S=150mt=10S∴ From equation  S=ut+12at2150=u10+12a102 ⇒u+5a=15..........(1) And also Distance travelled in 10th sec is 24m i.e n=10 &Sn=24 mFrom equation ∴Sn=u+an−12⇒24=u+a10−12⇒24=u+192a⇒2u+19a=48…………….(2)On solving (1) & (2)acceleration    a=2 m/s2......(3)And initial velocity  u=5 m /s