The mutual inductance between a primary and secondary circuits is 0.5 H. The resistances of the primary and the secondary circuits are 20 ohms and 5 ohms respectively. To generate a current of 0.4 A in the secondary, current in the primary must be changed at the rate of

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4.0 A/s

16.0 A/s

1.6 A/s

8.0 A/s

answer is A.

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Detailed Solution

e2=Mdi1dt⇒i2R2=Mdi1dt⇒0.4×5=0.5×di1dt⇒di1dt=4A/sec

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