Questions

n identical cells are joined in series with its two cells A and B in the loop with reversed polarities. Emf of each cell is E and internal resistance r. Potential difference across cell A or B is (here n > 4)

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2En

2E1−1n

4En

2E1−2n

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detailed solution

Correct option is D

The two opposite cells A and B will cancel two more other cells, so net emf will be n−4. So currentI=n−4Enr. Now p.d. across A or B= E + Ir they will be in charging state)=E+n−4En=2E 1−2n

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