Questions
n identical light bulbs, each designed to draw P power from a certain supply, are joined in series across that supply. The total power which they will draw is
detailed solution
Correct option is A
Let R be the resistance of each bulb. Resistance of n bulbs = n RCurrent in each bulb =i=VnRPower drawn by each bulbP2=i2R=V2n2R2×R=V2n2R=Pn2 ∵R=V2PTotal power drawn =n×Pn2=PnTalk to our academic expert!
Similar Questions
A resistor R is connected across a battery of emf 12 V. It observed that terminal potential differenceis 9 V and the power delivered to resistor is 18 W. Internal resistance of the battery ‘r’ and the resistance R are respectively
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