n identical light bulbs, each designed to draw P power from a certain supply, are joined in series across that supply. The total power which they will draw is
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a
Pn
b
np
c
Pn2
d
P
answer is A.
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Detailed Solution
Let R be the resistance of each bulb. Resistance of n bulbs = n RCurrent in each bulb =i=VnRPower drawn by each bulbP2=i2R=V2n2R2×R=V2n2R=Pn2 ∵R=V2PTotal power drawn =n×Pn2=Pn