Questions
N identical spherical drops charged to the same potential V are combined to form a big drop. The potential of the new drop will be
a
V
b
V / N
c
V×N
d
V×N2/3
detailed solution
Correct option is D
If the drops are conducting, then 43πR3=N43πr3⇒R=N1/3r. Final charge Q = NqSo final potential V=QR=NqN1/3r=V×N2/3Talk to our academic expert!
Similar Questions
A charge of is placed on each of the 64 identical drops of radius 2 cm. They are then combined to form a bigger drop. Find its potential
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