Questions
n moles of an ideal gas undergoes a process AB as shown in the given figure. Maximum temperature of the gas during the process is
detailed solution
Correct option is B
Since P-V graph of the process is a straight line and two points (V0, 2P0) and (2V0, P0) are known, its equation will be P−P0=2P0−P0V0−2V0V−2V0=P0V02V0−V∴ P=3P0−P0VV0According to equation for ideal gas,T=PVnR=3P0−P0VV0VnR=3P0V0V−P0V2nRV0 ........(i)For T to be maximum,dTdV=0 3P0V0−2P0V=0 or V=3V02 ........(ii)Putting this value in Eq. (i), we getTmax=3P0V03V02−P094V02nRV0=9P0V04nRTalk to our academic expert!
Similar Questions
The pressure and temperature of an ideal gas in a closed vessel are 720 kPa and 40oC respectively. If th of the gas is released from the vessel and the temperature of the remaining gas is raised to 353oC, the final pressure of the gas is
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