n moles of an ideal gas undergoes a process A→B as shown in the given figure. Maximum temperature of the gas during the process is

Since P-V graph of the process is a straight line and two points (V0, 2P0) and (2V0, P0) are known, its equation will be       P−P0=2P0−P0V0−2V0V−2V0=P0V02V0−V∴ P=3P0−P0VV0According to equation for ideal gas,T=PVnR=3P0−P0VV0VnR=3P0V0V−P0V2nRV0          ........(i)For T to be maximum,dTdV=0 3P0V0−2P0V=0 or  V=3V02                     ........(ii)Putting this value in Eq. (i), we getTmax=3P0V03V02−P094V02nRV0=9P0V04nR