'n' moles of an ideal gas undergoes a process A→B as shown in the figure. The maximum temperature of the gas during the process will be :

The equation for the line is P=−P0 V0 V+3PUsing,P=nRTV⇒nRTV0+P0 V2=3P0 V0 For temperature to be maximum dTdV=0Differentiating wrt V we getnRV0dTdV+P0(2 V)=3P0 V0⇒dTdV=3P0 V0−2P0 VnRV0=0V=3 V02 ∴P=3P02∴Tmax=9PoVo4nR