Questions
'n' moles of an ideal gas undergoes a process as shown in the figure. The maximum temperature of the gas during the process will be :
detailed solution
Correct option is C
The equation for the line is P=−P0 V0 V+3PUsing,P=nRTV⇒nRTV0+P0 V2=3P0 V0 For temperature to be maximum dTdV=0Differentiating wrt V we getnRV0dTdV+P0(2 V)=3P0 V0⇒dTdV=3P0 V0−2P0 VnRV0=0V=3 V02 ∴P=3P02∴Tmax=9PoVo4nRTalk to our academic expert!
Similar Questions
Two identical containers A and B have frictionless pistons. They contain the same volume of an ideal gas at the same temperature. The mass of the gas in A is mA and that in B is mB. The gas in each cylinder is now allowed to expand isothermally to double the initial volume. The change in the pressure in A and B, respectively, is and 1.5. Then
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