Questions
An n – p – n transistor is used in common emitter configuration with an amplifier with load resistance. Signal voltage of 10 mV is applied across the base – emitter. This produces a 3mA change in the collector current and 15 change in the base current of the amplifier. The input resistance and voltage gain are
detailed solution
Correct option is C
∴Voltage gain =VoutputVinput =Rl×△IcVin =1×103×3×10−310×10−3=300Input Resistance : Rin=Viniin=Vinib=10×10−315×10−6 =10×10315=0.67×103Ω =0.67kΩTalk to our academic expert!
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For a transistor, the current amplification factor is 0.8. The transistor is connected in common-emitter configuration. The change in the collector current when the base current changes by 6 mA is
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