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Q.

An n – p – n transistor is used in common emitter configuration with an amplifier with 1kΩ  load resistance. Signal voltage of 10 mV is applied across the base – emitter. This produces a 3mA change in the collector current and 15μA  change in the base current of the amplifier. The input resistance and voltage gain are

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a

0.67kΩ, 200

b

0.33kΩ, 1.5

c

0.67kΩ, 300

d

0.33kΩ, 300

answer is C.

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Detailed Solution

∴Voltage gain =VoutputVinput                                                           =Rl×△IcVin                              =1×103×3×10−310×10−3=300Input Resistance : Rin=Viniin=Vinib=10×10−315×10−6                                                                =10×10315=0.67×103Ω =0.67kΩ
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