The n rows each containing m cells in series are joined in parallel. Maximum current is taken from this combination across an external resistance of $$3$$ Ω. If the total number of cells used are $$24$$ internal resistance of each cell is $$0.5$$ Ω .Then

Question

The n rows each containing m cells in series are joined in parallel. Maximum current is taken from this combination across an external resistance of  $$3$$ Ω. If the total number of cells used are $$24$$ internal resistance of each cell is $$0.5$$ Ω .Then

Infinity Learn · Accepted Answer

n →number of rows m →total no of cells in a row R $$=$$ $$3$$ Ω , r $$=$$ $$0.5$$ Ω mn $$=$$ $$24$$   For maximum current in R $$R=mrn$$ ⇒$$3=mn$$ × $$0.5$$ ⇒m $$=$$ $$6n$$ Now use $$mn=24$$ ⇒$$6n2$$ $$=$$ $$24$$ ⇒n $$=$$ $$2$$ , $$m=12$$

The n rows each containing m cells in series are joined in parallel. Maximum current is taken from this combination across an external resistance of $3 Ω$ . If the total number of cells used are 24 internal resistance of each cell is $0.5 Ω$ .Then

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The n rows each containing m cells in series are joined in parallel. Maximum current is taken from this combination across an external resistance of 3 Ω. If the total number of cells used are 24 internal resistance of each cell is 0.5 Ω .Then

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The n rows each containing m cells in series are joined in parallel. Maximum current is taken from this combination across an external resistance of $3 Ω$ . If the total number of cells used are 24 internal resistance of each cell is $0.5 Ω$ .Then