n small drops of same size are charged to V volt each. If they coalesce to form a single large drop, then its potential will be

Let R be the radius of big drop and r, radius of small drop.∴ 43πR3=n43πr3  or  R=r(n)1/3Total charge on big drop = n qPotential of bigger drop=14πε0×nqr(n)1/3=14πε0×qr×n2/3=Vn2/3