A 20 N stone is suspended from a wire and its length changes by 1%. If the Young's modulus of the material of the wire is 2 x 1011 N /m2, the area of cross-section of the wire is
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a
10−3mm2
b
10−2mm2
c
10−1mm2
d
1mm2
answer is B.
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Detailed Solution
Given that l/L=1100A=FLYl=202×1011(100)m2=10−8m2=10−2mm2