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In the n^th orbit, the energy of an electron $E_{N} = - \frac{13 .6}{n^{2}} eV$ for hydrogen atom. The energy required to take the electron from first orbit to second orbit will be

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10.2eV

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detailed solution

Correct option is A

E1→2=−3.4−(13.6)=+10.2eV

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In the nth orbit, the energy of an electron EN=−13.6n2eV for hydrogen atom. The energy required to take the electron from first orbit to second orbit will be

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In the n^th orbit, the energy of an electron $E_{N} = - \frac{13 .6}{n^{2}} eV$ for hydrogen atom. The energy required to take the electron from first orbit to second orbit will be