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A narrow pipe with a cross section area ‘A’ and length ‘L’ is half filled with liquid of density ρ and is rotating with a constant angular velocity 'ω’ about vertical axis passing through its open end as shown in figure. A small hole of area ‘a’ (a << A) is made at its closed end at t = 0. The time in which entire liquid will come out of the pipe will be


 

a
πA3aω
b
Aaω
c
A2aω
d
πA6aω

detailed solution

Correct option is A

Pressure at 1,2 and 3 are P0,P and P0 respectively.Consider an element of width dx located at distance x from axis. This element is in circular motion.P+dPA−PA=dmω2x​⇒dPA=ρAdxω2x​⇒∫P0PdP=ρω2∫rLxdx⇒P−P0=ρ2L2−r2ω2Since, a<

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A cylindrical drum, open at the top, contains 90 litres of water. It drains out through a small opening at the bottom. 30 litres of water comes out in timet1 ,  the next 30 litres in further time t2 and the last  30 litres in further timet3 . Then :


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