First slide

Equilibrium of a particle

Question

Natural length of the spring is 40 cm and its spring constant is 4000 N m^-1. A mass of 20 kg is hung from it. The extension produced in the spring is (Given g = 9.8 m s^-2)

Moderate

A

4.9 cm
B

0.49 cm
C

9.4 cm
D

0.94 cm

Solution

In equilibrium, $kx = mg$
$∴ x = \frac{mg}{k} = \frac{20 \times 9 .8}{4000} = 0 .049 m = 4 .9 cm$

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