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Q.

The near point of a person is 50 cm and the far point is 1.5 m. The spectacles required for reading purpose and for seeing distant objects are respectively :

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a

+2D,−23D

b

+23D,−2D

c

−2D,+23D

d

−23D,+2D

answer is D.

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Detailed Solution

1−50−1−(25)=1f1f=150⇒P=100f(cm)=10050=2DNow in second case1−150−1∞=1f′f′=−150cm⇒ P=100−150=−23D
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