The near point of a person is 50 cm and the far point is 1.5 m. The spectacles required for reading purpose and for seeing distant objects are respectively :
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a
+2D,−23D
b
+23D,−2D
c
−2D,+23D
d
−23D,+2D
answer is D.
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Detailed Solution
1−50−1−(25)=1f1f=150⇒P=100f(cm)=10050=2DNow in second case1−150−1∞=1f′f′=−150cm⇒ P=100−150=−23D