The neck and bottom of a bottle are 3 cm and 15 cm in radius respectively. If the cork is pressed with a force 12 N in the neck of the bottle, then force exerted on the bottom of the bottle is:
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a
30 N
b
150 N
c
300 N
d
600 N
answer is C.
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Detailed Solution
From Pascal's law F2A2=F1A1 ⇒F2=A2A1F1=r2r12×F1 =15×10-23×10-22×12=300 N