The needle of a deflection galvanometer shows a deflection of 60o due to a short bar magnet at a certain distance in tan A position. If the distance is doubled, the deflection is
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a
sin-138
b
cos-138
c
tan-138
d
cot-138
answer is C.
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Detailed Solution
For short bar magnet in tan A-position, μ04π2Md3=BH tanθ ........(i)When distance is doubled, then new deflection θ' is given by μ04π2M2d3=BH tanθ ' ........(ii)∴tan θ'tan θ=18⇒tan θ'=tan θ8=tan 60o8=38⇒θ'=tan-138