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Q.

In a neon discharge tube 2.9 ×  1018  Ne+ ions move to the right each second while 1.2 ×  1018  electrons move to the left per second. Electron charge is 1.6 ×  10−19C.  The current in the discharge tube

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a

1 A towards right

b

0.66 A towards right

c

0.66 A towards left

d

Zero

answer is B.

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Detailed Solution

Net current i=i+ +i− = n+ q+t + n− q−tNet current i=i+ +i− = n+ q+t + n− q−t⇒ i=n+ t×e + n−t=2.9 ×  1018 × 1.6 ×  10−19+1.2 ×  1018 × 1.6 ×  10−19⇒ i=0.66 A.
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