In a neon discharge tube 2.9 × 1018 Ne+ ions move to the right each second while 1.2 × 1018 electrons move to the left per second. Electron charge is 1.6 × 10−19C. The current in the discharge tube
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a
1 A towards right
b
0.66 A towards right
c
0.66 A towards left
d
Zero
answer is B.
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Detailed Solution
Net current i=i+ +i− = n+ q+t + n− q−tNet current i=i+ +i− = n+ q+t + n− q−t⇒ i=n+ t×e + n−t=2.9 × 1018 × 1.6 × 10−19+1.2 × 1018 × 1.6 × 10−19⇒ i=0.66 A.