In the network shown, the charge on the capacitor in steady state is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
12 μC
b
24 μC
c
8 μC
d
16 μC
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
(4)In steady state, Current Through 2Ω resistor, i=102+3A=2A.∴ V=Voltage drop across 2ΩVoltage drop across the capacitor.=2 × 2 volt=4 volt∴ Q=charge = 4 × 4=16μC