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Q.

In the network shown, the charge on the capacitor in steady state is

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a

12  μC

b

24  μC

c

8  μC

d

16  μC

answer is D.

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Detailed Solution

(4)In steady state, Current Through 2Ω  resistor,  i=102+3A=2A.∴  V=Voltage  drop  across 2ΩVoltage drop across the capacitor.=2  ×  2  volt=4  volt∴   Q=charge  =  4 × 4=16μC
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