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In the network shown, the charge on the capacitor in steady state is

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12 μC

24 μC

8 μC

16 μC

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detailed solution

Correct option is D

(4)In steady state, Current Through 2Ω resistor, i=102+3A=2A.∴ V=Voltage drop across 2ΩVoltage drop across the capacitor.=2 × 2 volt=4 volt∴ Q=charge = 4 × 4=16μC

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