First slide

Capacitance

Question

In the network shown, the charge on the capacitor in steady state is

Moderate

A

$12 μ C$
B

$24 μ C$
C

$8 μ C$
D

$16 μ C$

Solution

(4)
In steady state, Current Through $2 Ω r e s i s t o r, i = \frac{10}{2 + 3} A = 2 A .$
$∴ V = V o l t a g e d r o p a c r o s s 2 Ω$
Voltage drop across the capacitor.
$\begin{array}{l} = 2 \times 2 v o l t = 4 v o l t \\ ∴ Q = c h \arg e = 4 \times 4 = 16 μ C \end{array}$

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