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Questions  

For the network shown in fig, the value of n current is

a
5 V/9
b
9V/35
c
18 V/5
d
5v/18

detailed solution

Correct option is D

The circuit is a balanced Wheatstone bridge. Therefore, the resistance 4Ω is  and can be eliminated. The resistances 4 Ω and 2Ω are in series and their equivalent resistance is 6Ω. Similarly, the equivalent resistance of 6Ω and 3Ω resistances is 9 Ω The equivalent resistance of the circuit is given byReq=6×96+9=185∴ i=VReq=V(18/5)=5V18

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