In the network shown in figure, $$1$$ and $$2$$ are identical parallel plate capacitors, potential difference across capacitor $$1$$ is $$12$$ volt. Now a dielectric slab having k $$=$$ $$3$$ is inserted into the space between the plates of capacitor $$1$$ and the slab completely fills the space. What will be the potential difference across capacitor $$2$$?

Question

Infinity Learn · Accepted Answer

E $$=$$ emf of the battery $$=$$ (12+12) volt $$=$$ $$24$$ volt.After the slab is inserted in capacitor $$1$$, equivalent capacitance $$Ce=kcxckc+c=3c3+1=3c4$$∴Q $$=$$ Charge on each capacitor $$=3c4$$ x $$24=18c$$∴Potential difference between the plates of $$2$$ $$=18cc=18$$ volt

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