Q.

In the network shown in figure, 1 and 2 are identical parallel plate capacitors, potential difference across capacitor 1 is 12 volt. Now a dielectric slab having k = 3 is inserted into the space between the plates of capacitor 1 and the slab completely fills the space. What will be the potential difference across capacitor 2?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

16 volt

b

18 volt

c

20 volt

d

8 volt

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

E = emf of the battery = (12+12) volt = 24 volt.After the slab is inserted in capacitor 1, equivalent capacitance Ce=kcxckc+c=3c3+1=3c4∴Q = Charge on each capacitor =3c4 x 24=18c∴Potential difference between the plates of 2 =18cc=18 volt
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
whats app icon
In the network shown in figure, 1 and 2 are identical parallel plate capacitors, potential difference across capacitor 1 is 12 volt. Now a dielectric slab having k = 3 is inserted into the space between the plates of capacitor 1 and the slab completely fills the space. What will be the potential difference across capacitor 2?