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Q.

In the network shown in figure, 1 and 2 are identical parallel plate capacitors, potential difference across capacitor 1 is 12 volt. Now a dielectric slab having k = 3 is inserted into the space between the plates of capacitor 1 and the slab completely fills the space. What will be the potential difference across capacitor 2?

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a

16 volt

b

18 volt

c

20 volt

d

8 volt

answer is B.

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Detailed Solution

E = emf of the battery = (12+12) volt = 24 volt.After the slab is inserted in capacitor 1, equivalent capacitance Ce=kcxckc+c=3c3+1=3c4∴Q = Charge on each capacitor =3c4 x 24=18c∴Potential difference between the plates of 2 =18cc=18 volt
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