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In the network shown in figure, charge stored in the capacitor is

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8 μC

6 μC

2 μC

4 μC

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detailed solution

Correct option is A

when the capacitor is fully charged, current through the upper branch and lower branch, i1=i2=124+2A=2A∴ VA+2×i1−4×i2=VB⇒VA−VB=4 volt∴ Q2=VA−VB=4 ⇒Q=8 μC

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