The network shown in the figure is a part of a complete circuit. If at a certain instant the current i is 5A and is decreasing at the rate of 103 A/s then VA- VB is
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a
5V
b
10V
c
15V
d
20V
answer is C.
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Detailed Solution
By using Kirchhoff's voltage lawVA−iR+E−Ldidt=VB ⇒VB−VA=15 -(5)(1)-(0.005)(-1000) ⇒VB−VA=15V