First slide

Capacitance

Question

In the network shown, if $C = 2 μ F$ , equivalent capacitance between A and B is

Moderate

A

$1 μ F$
B

$\frac{4}{3} μ F$
C

$\frac{3}{4} μ F$
D

$4 μ F$

Solution

The given circuit can be reduced to one shown in figure.
$∴ C_{A B} = C + C = 2 C = 2 \times 2 μ F = 4 μ F$

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