Questions
In the network shown, if power dissipated in the resistor is 24 watt, reading of the ideal voltmeter V is
a
2 Volt
b
1.5 Volt
c
1.75 Volt
d
2.5 Volt
detailed solution
Correct option is A
(1)If current through 6Ω resistor is i,Then i2 × 6=24 ⇒ i=2A.The upper branch and lower branch of the circuit have the same resistance 2+4Ω i.e., 6ΩTherefore current through each branch is 1A.∴ VP+2×1−4×1=VQ ⇒ VP−VQ=4-2=2 volt.Talk to our academic expert!
Similar Questions
A strip of copper and another of germanium are cooled from room temperature to 80 K. The resistance of
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions
