Questions
In the network shown initially is closed and is open. Now is opened and at the same time is closed. Find the loss of energy in the process. [Given ]
detailed solution
Correct option is B
Initially energy stored in the system Ui=12CV2Finally energy stored in the systemUf=CV22C+C=14CV2∴ Lost energy=Ui−Uf=12CV2−14CV2=14CV2=14×2×62μJ=18 μJTalk to our academic expert!
Similar Questions
Before connecting to the circuit shown in figure, all capacitors were uncharged. The circuit now is in steady state. Now the switch S is closed. During the time the steady state is reached again
| Column - I | Column - II | ||
| (i) | Charge on C1 | p. | increases |
| (ii) | Charge on C2 | q. | decreases |
| (iii) | Charge on C3 | r. | remains same |
| (iv) | Charge on C4 | s. | becomes zero |
Now, match the given columns and select the correct option from the codes given below.
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