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Q.

In the network shown initially S1 is closed and S2 is open. Now S1 is opened and at the same time S2 is closed. Find the loss of energy in the process. [Given C=2μF, V= 6 volt]

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a

24 μJ

b

18 μJ

c

12 μJ

d

36 μJ

answer is B.

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Detailed Solution

Initially energy stored in the system Ui=12CV2Finally energy stored in the systemUf=CV22C+C=14CV2∴ Lost energy=Ui−Uf=12CV2−14CV2=14CV2=14×2×62μJ=18 μJ

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