A neutron having mass of 1.67×10−27kg and moving at 108m/s collides with a deutron at rest and sticks to it. If the mass of the deutron is 3.34×10−27kg then the speed of the combination is

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2.56×103m/s

2.98×105m/s

3.33×107m/s

5.01×109m/s

answer is C.

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Detailed Solution

According to law of conservation of momentum.Momentum of neutron = Momentum of combination⇒1.67×10−27×108=(1.67×10−27+3.34×10−27) v∴v=3.33×107 m/s

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