First slide
Fluid dynamics
Question

 A non viscous liquid of constant density 500 kg/m3 flows in a variable cross-sectional tube [Fig. (6)]. The
 

area of cross section of the tube at the two points P and Q at heights of 3 m and 6 m are 2x10-3 m3 and 4x10-3 m3 respectively. The work done per unit
volume by the forces of gravity as fluid flows from point P to Q is

Easy
Solution

We know that
 Work done per unit volume by force of gravity = - 6[s1gs in potential energy per unit volume
 W=ΔU=ρgh2h1 =ρg(63)=3ρg =3×500×98=147×104J/m3

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