A non viscous liquid of constant density 500 kg/m3 flows in a variable cross-sectional tube [Fig. (6)]. The area of cross section of the tube at the two points P and Q at heights of 3 m and 6 m are 2x10-3 m3 and 4x10-3 m3 respectively. The work done per unitvolume by the forces of gravity as fluid flows from point P to Q is
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a
29⋅4J/m3
b
−1⋅47×104J/m3
c
−2⋅94×104J/m3
d
none of these
answer is B.
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Detailed Solution
We know that Work done per unit volume by force of gravity = - 6[s1gs in potential energy per unit volume∴ W=−ΔU=−ρgh2−h1 =−ρg(6−3)=−3ρg =−3×500×9⋅8=−1⋅47×104J/m3