The normal density of gold is p and its bulk modulus is K The increase in density of a lump of gold when a pressure P applied uniformly on all side is
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a
ρP/K
b
ρK/P
c
P/ρK
d
K/ρP
answer is A.
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Detailed Solution
K=P(ΔV/V) or ΔVV=PK………..(1)Further.ρ=MV and ρ′=MV−ΔV∴ ρ′ρ=VV−ΔV=1{1−(ΔV/V)}=1−ΔVV−1=1+ΔVV………..(2)From eqs. (1) and (2), we getρ′ρ=1+PK or ρ′ρ−1=PKor ρ′−ρρ=ρK or ρ′−ρ=ρPK