Normal reaction N is a force exerted by the surface on the block perpendicular to the surface of contact. A block of mass 1 kg is placed on inclined plane of inclination 370 as shown in the figure. Find the component of normal reaction N = 8 N on the block x-axis and y-axis.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
-4.8 N, 6.4 N
b
6.4 N, 4.8 N
c
10 N, 0 N
d
4.8 N, 6.4 N
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The x-component of normal reaction N is- N cos 530 = -8×35 = -4.8 NThe y-component of normal reaction N is N sin 530= 8×45 = 325 = 6.4 N
Normal reaction N is a force exerted by the surface on the block perpendicular to the surface of contact. A block of mass 1 kg is placed on inclined plane of inclination 370 as shown in the figure. Find the component of normal reaction N = 8 N on the block x-axis and y-axis.