First slide

Different types of Forces

Question

Normal reaction N is a force exerted by the surface on the block perpendicular to the surface of contact. A block of mass 1 kg is placed on inclined plane of inclination $37^{0} as shown in the figure .$ Find the component of normal reaction N = 8 N on the block x-axis and y-axis.

Moderate

A

-4.8 N, 6.4 N
B

6.4 N, 4.8 N
C

10 N, 0 N
D

4.8 N, 6.4 N

Solution

The x-component of normal reaction N is
$- N \cos 53^{0} = - 8 \times \frac{3}{5} = - 4.8 N$
The y-component of normal reaction N is N ${sin 53}^{0}$
$= 8 \times \frac{4}{5} = \frac{32}{5} = 6.4 N$

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