Normal reaction N is a force exerted by the surface on the block perpendicular to the surface of contact. A block of mass $$1$$ kg is placed on inclined plane of inclination $$370$$ as shown in the figure. Find the component of normal reaction N $$=$$ $$8$$ N on the block $$x-axis$$ and $$y-axis$$.

Question

Normal reaction N is a force exerted by the surface on the block perpendicular to the surface of contact. A block of mass $$1$$ kg is placed on inclined plane of inclination $$370$$ as shown in the figure.  Find the component of normal reaction N $$=$$ $$8$$ N on the block $$x-axis$$ and $$y-axis$$.

Infinity Learn · Accepted Answer

The $$x-component$$ of normal reaction N $$is-$$ N $$cos$$ $$530$$ $$=$$ $$-8$$×$$35$$ $$=$$ $$-4.8$$ NThe $$y-component$$ of normal reaction N is N $$sin$$ $$530=$$ $$8$$×$$45$$ $$=$$ $$325$$ $$=$$ $$6.4$$ N

Normal reaction N is a force exerted by the surface on the block perpendicular to the surface of contact. A block of mass 1 kg is placed on inclined plane of inclination $37^{0} as shown in the figure .$ Find the component of normal reaction N = 8 N on the block x-axis and y-axis.

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Normal reaction N is a force exerted by the surface on the block perpendicular to the surface of contact. A block of mass 1 kg is placed on inclined plane of inclination 370 as shown in the figure. Find the component of normal reaction N = 8 N on the block x-axis and y-axis.

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Normal reaction N is a force exerted by the surface on the block perpendicular to the surface of contact. A block of mass 1 kg is placed on inclined plane of inclination $37^{0} as shown in the figure .$ Find the component of normal reaction N = 8 N on the block x-axis and y-axis.