In an n-p-n transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector, the emitter current (IE) and base current (IB) are given by

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IB=−1mA,IB=9mA

IE=9mA,IB=−1mA

IE=1mA,IB=11mA

IE=11mA,IB=1mA

answer is D.

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Detailed Solution

(4) IE=IB+IC , 0.9 IE=IC=10mA IE=11 mA,IB=IE−IC=11−10=1mA

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