In an NPN transistor circuit the collector current is 10mA. If 90% of the electrons are able to reach the collector from emitter a. The emitter current will be 9mA b. The emitter current will be 11mA c The base current will be 1.1 mA d. The base current will be 0.1 mA
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a
b and d are correct
b
a and c are correct
c
a and d are correct
d
b and c are correct
answer is D.
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Detailed Solution
90% of emitter current is collector current and 10 % will be base current 90% of IE is 10mA IE=10×10090=11.1 mA IB=1.1 mA