In an NPN transistor circuit the collector current is 10mA. If 90% of the electrons are able to reach the collector from emitter a. The emitter current will be 9mA b. The emitter current will be 11mA c The base current will be 1.1 mA d. The base current will be 0.1 mA

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b and d are correct

a and c are correct

a and d are correct

b and c are correct

answer is D.

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Detailed Solution

90% of emitter current is collector current and 10 % will be base current 90% of IE is 10mA IE=10×10090=11.1 mA IB=1.1 mA

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