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Q.

In an NPN transistor circuit, the collector current is 10rnA.If 90% of the electrons emitted reach the collector, the emitter current (iE) and base current (iB) are given by

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a

iE=1 mA, iB=9 mA

b

iE=9 mA, iB=-1 mA

c

iE=1 mA, iB=11 mA

d

iE=11 mA, iB=1 mA

answer is D.

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Detailed Solution

iC=90100×iE⇒10=0.9×iE⇒iE=11 mA Also, iE=iB+iC⇒11-10=1 mA
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