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In an NPN transistor circuit, the collector current is 10rnA.If 90% of the electrons emitted reach the collector, the emitter current ( $i_{E}$ ) and base current ( $i_{B}$ ) are given by

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iE=1 mA, iB=9 mA

iE=9 mA, iB=-1 mA

iE=1 mA, iB=11 mA

iE=11 mA, iB=1 mA

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detailed solution

Correct option is D

iC=90100×iE⇒10=0.9×iE⇒iE=11 mA Also, iE=iB+iC⇒11-10=1 mA

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In an NPN transistor circuit, the collector current is 10rnA.If 90% of the electrons emitted reach the collector, the emitter current (iE) and base current (iB) are given by

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In an NPN transistor circuit, the collector current is 10rnA.If 90% of the electrons emitted reach the collector, the emitter current ( $i_{E}$ ) and base current ( $i_{B}$ ) are given by