Transistor

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Question

In an n-p-n transistor circuit the emitter current is 10 mA. If 10% of the emitted electrons are lost in the base, the base current is

Easy

Solution

for any transistor $I_{E} = I_{B} + I_{C}$
here
$I_{B} = \frac{10 I_{E}}{100} = \frac{10 \times 10}{100} = 1 mA and I_{c} = 9 mA$

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