First slide

Transistors

Question

In an n-p-n transistor, the collector current is 10 mA, if 90% of the electrons emitted reach the collector, the emitter current I_E and base current I_B are given by

Moderate

A

$I_{E} = - 1 mA, I_{B} = 9 mA$
B

$I_{E} = 9 mA, I_{B} = - 1 mA$
C

$I_{E} = 1 mA, I_{B} = 11 mA$
D

$I_{E} = 11 mA, I_{B} = 1 mA$

Solution

As, collector current, $I_{C} = \frac{90}{100} \times I_{E}$
where, l_E = emitter current.
$\begin{array}{l} \Rightarrow 10 = 0 .9 \times I_{E} \\ \Rightarrow I_{E} = 11 mA \end{array}$
Also, $I_{E} = I_{B} + I_{C}$
Base current, $I_{B} = I_{E} - I_{C}$
$= 11 - 10 = 1 mA$

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