In an n-p-n transistor, the collector current is 10 mA, if 90% of the electrons emitted reach the collector, the emitter current IE and base current IB are given by

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IE=−1mA, IB=9mA

IE=9mA, IB=−1mA

IE=1mA, IB=11mA

IE=11mA, IB=1mA

answer is D.

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Detailed Solution

As, collector current, IC=90100×IEwhere, lE = emitter current.⇒ 10=0.9×IE⇒ IE=11mAAlso, IE=IB+ICBase current, IB=IE−IC =11−10=1mA

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