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Q.

In NPN transistor the collector current is 10mA. If 90% of electrons emitted reach the collector, then

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a

emitter current will be 9mA

b

emitter current will be 11.1mA

c

base current will be 0.1mA

d

base current will be 0.01mA

answer is B.

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Detailed Solution

Given : Collector Current =Ic = 10 mA90% of electron emitted = collected by collector ⇒90100×IE = Ic⇒IE = 10 mA0.9 = 11.1 mA

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