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Questions  

In NPN transistor the collector current is 8mA.  If 80% of electrons emitted reach the collector, then

a
emitter current will be 9mA
b
emitter current will be 8mA
c
Base current will be 10mA
d
Base current will be 2mA

detailed solution

Correct option is D

Collector Current : Ic=8mA Given :80% of emitted electrons = Collected by collector ⇒0.8×IE = IC⇒IE=Ic0.8=8mA0.8=10mANow, IE =IB + Ic⇒IB=IE−Ic=10−8=2mA

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In an n-p-n transistor, the collector current is 10 mA, if 90% of the electrons emitted reach the collector, the emitter current IE and base current IB are given by


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