First slide

Transistors

Question

In NPN transistor the collector current is 8mA. If 80% of electrons emitted reach the collector, then

Moderate

A

emitter current will be 9mA
B

emitter current will be 8mA
C

Base current will be 10mA
D

Base current will be 2mA

Solution

$\begin{array}{l} C o l l e c t o r C u r r e n t : I_{c} = 8 m A \\ G i v e n : \\ 80 % o f e m i t t e d e l e c t r o n s = C o l l e c t e d b y c o l l e c t o r \\ \Rightarrow 0.8 \times I_{E} = I_{C} \\ \Rightarrow I_{E} = \frac{I_{c}}{0.8} = \frac{8 m A}{0.8} = 10 m A \\ N o w, \\ I_{E} = I_{B} + I_{c} \\ \Rightarrow I_{B} = I_{E} - I_{c} = 10 - 8 = 2 m A \end{array}$

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