First slide

Transistor

Question

A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of $800 Ω$ is connected in the collector circuit and the voltage drop across it is $0.8 V$ . If the current amplification factor is 0.96 and the input resistance of the circuit is $192 Ω,$ the voltage gain and the power gain of the amplifier will respectively be

Moderate

A

4, 4
B

4, 3.69
C

4, 3.84
D

3.69, 3.84

Solution

$Here, R_{O} = 800 Ω, R_{i} = 192 Ω, current gain, β = 0.96$
$Voltage gain = Current gain \times Resistance gain$
$= 0.96 \times \frac{800}{192} = 4$
$Power gain = [Current gain] \times [Voltage gain]$
$= 0.96 \times 4 = 3.84$

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