Q.

A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of  800Ω  is connected in the collector circuit and the voltage drop across it is  0.8V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192Ω,the voltage gain and the power gain of the amplifier will respectively be

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

4, 4

b

4, 3.69

c

4, 3.84

d

3.69, 3.84

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Here, RO=800Ω,Ri=192Ω , current gain, β=0.96 Voltage gain = Current gain × Resistance gain =0.96×800192=4 Power gain =[ Current gain ]×[ Voltage gain ]=0.96×4=3.84
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
whats app icon