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In an n–p–n transistor, current gain for common emitter configuration is 80. If the emitter current be 8.1 mA, Then the base current is ____

a
0.1  μA
b
0.01  μA
c
0.1  mA
d
0.01  mA

detailed solution

Correct option is C

β=ICIBAlso,   IC = IE – IBThis givens, IB=IE81=8.181  mA=0.1   mA

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