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Q.

In an n–p–n transistor, current gain for common emitter configuration is 80. If the emitter current be 8.1 mA, Then the base current is ____

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a

0.1  μA

b

0.01  μA

c

0.1  mA

d

0.01  mA

answer is C.

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Detailed Solution

β=ICIBAlso,   IC = IE – IBThis givens, IB=IE81=8.181  mA=0.1   mA
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