In a n-p-n transistor, 1010 electrons enter the emitter in 10-6 s and 4% of the electrons are lost in base. The current transfer ratio will be

Number of electrons reaching the collector,                                              nC=96100×1010=0.96×1010Emitter current, IE=nE×etCollector current, IC=nC×etThus, current transfer ratio,                                       α=ICIE=nCnE=0.96×10101010=0.96