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In an n-p-n transistor, the emitter current is 1mA and α=0.95 . The base current and collector currents are

a
0.15mA, 0.85mA
b
1.95mA, 0.05mA
c
0.95mA, 0.05mA
d
0.05mA, 0.95mA

detailed solution

Correct option is C

ΔIE=1mA α=0.95α=ΔICΔIE=and ΔIE=1mAΔIC=0.95×1mA=0.95mAΔIb=ΔIE-ΔIC=1-0.95=0.05mA

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