First slide

Transistors

Question

A n-p-n transistor operates in a common emitter mode as shown below. Given that $I_{c} = 4 mA, V_{CE} = 4 V, V_{BE} = 0.6 V . Then R_{L} is$

Easy

A

$1 kΩ$
B

$18.5 kΩ$
C

$185 kΩ$
D

$1.85 kΩ$

Solution

$V_{C E} = V_{C C} - I_{C} R_{L}$
$∴ R_{L} = \frac{V_{C C} - V_{C E}}{I_{C}} = \frac{8 V - 4 V}{4 \times 10^{- 3} A} = 10^{3} Ω = 1 kΩ$

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