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Q.

A n-p-n transistor operates in a common emitter mode as shown below. Given that Ic=4mA,VCE=4V,VBE=0.6V. Then RL is

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a

1 kΩ

b

18.5 kΩ

c

185 kΩ

d

1.85 kΩ

answer is A.

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Detailed Solution

VCE=VCC−ICRL∴ RL=VCC−VCEIC=8V−4V4×10−3A=103Ω=1kΩ
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A n-p-n transistor operates in a common emitter mode as shown below. Given that Ic=4mA,VCE=4V,VBE=0.6V. Then RL is