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In a nuclear experiment a 1 Mev proton moves in a uniform magnetic field in a circular path of a certain radius.The energy of a deuteron which will circulate in the same orbit in the same magnetic field will be
detailed solution
Correct option is C
ω=QBm,Speed v=2km∴K= 12mω2R2=Q2B2R22m∴ kdkp=Qd2Qp2×mpmd=(1)2×12=12∴ kd=0.5 MevTalk to our academic expert!
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A charged particle of mass m, carrying a charge Q is projected from the origin with a velocity . A uniform magnetic field exists in that region. Then maximum distance of the particle from x-axis is
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