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Q.

A nuclear reaction along with the masses of the particle taking part in it is as follows:A1.002+B1.004→C1.001+D1.003+QMeVThe energy Q liberated in the reaction is

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a

1.234 MeV

b

0.931 MeV

c

0.465 MeV

d

1.862 MeV

answer is D.

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Detailed Solution

Q=(1.002+1.004−1.001−1.003)931.5
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