The nuclear reaction $$2H+2H$$→$$4He$$ (mass$$ of deuteron $$=$$ $$2.0141$$ a.m.u. and mass of He $$=$$ $$4.0024$$ a.m.u.$$) is

Correct option is 1Fusion reaction releasing 24 MeV energy

Questions

The nuclear reaction $^{2} H +^{2} H \to^{4} He$ (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is

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Fusion reaction releasing 24 MeV energy

Fusion reaction absorbing 24 MeV energy

Fission reaction releasing 0.0258 MeV energy

Fission reaction absorbing 0.0258 MeV energy

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detailed solution

Correct option is A

Total mass of reactants =(2.0141)×2=4.0282amu Total mass of products =4.0024amu Mass defect =4.0282amu−4.0024amu=0.0258amu ∴ Energy released E=931×0.0258=24MeV

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The nuclear reaction 2H+2H→4He (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is

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The nuclear reaction $^{2} H +^{2} H \to^{4} He$ (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is