First slide

Energy released in nuclear reactions -Q-value

Question

The nuclear reaction ${}_{1}^{1}H + {}_{1}^{1}H = {}_{2}^{4}{He}$ (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is

Moderate

A

Fusion reaction releasing 24 MeV energy
B

Fusion reaction absorbing 24 MeV energy
C

Fission reaction releasing 0.0258 MeV energy
D

Fission reaction absorbing 0.0258 MeV energy

Solution

Total mass of reactants
= (2.0141) x 2 = 4.0282 amu
Total mass of products = 4.0024 amu
Mass defect = 4.0282 amu — 4.0024 amu
= 0.0258 amu
$∴$ Energy released E = 931 x 0.0258= 24 MeV

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