The nuclear reaction H 11 + H 11 = He 24 (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is

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Fusion reaction releasing 24 MeV energy

Fusion reaction absorbing 24 MeV energy

Fission reaction releasing 0.0258 MeV energy

Fission reaction absorbing 0.0258 MeV energy

answer is A.

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Detailed Solution

Total mass of reactants= (2.0141) x 2 = 4.0282 amuTotal mass of products = 4.0024 amuMass defect = 4.0282 amu — 4.0024 amu = 0.0258 amu∴Energy released E = 931 x 0.0258= 24 MeV

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